![]() ![]() Programming model, demonstrating how to map both API and concepts from the The purpose of this example is to compare the CUDA and SYCL This section represents a step-by-step CUDA and SYCL example for adding two Into its SYCL equivalent, which can be used for either option above.įor the last case, there is only one source code that can be executed on NVIDIA In the following subsections we describe how to convert existing CUDA code The first two approaches require the SYCL and the CUDA source separated in the source using pre-processor macros and different build systems. However, it may not offer all the features of the latest NVIDIA hardware, since they may not be available on the SYCL implementation. This is the simplest to maintain, as once the code is on C++ and SYCL, there is only one single source to maintain. A third possible approach is simply to port all the CUDA code to SYCL, and use a SYCL implementation capable of running on NVIDIA devices via a PTX backend.The actual implementation is provided by the specific This is the approach followed by the standard In the example below,ĭifferent back-ends implement different functionality for the library, but the mainįunctionality and the interface is the same. ![]() SYCL versions implement their own back-ends and at compile time, based on the chosenĬompiler, either the CUDA or SYCL back-ends will be selected. In the second approach, we use template specialization where the CUDA and.PtrA = static_cast(SYCLmalloc(N * sizeof(float), pMap)) This pointer is a number that identifies the buffer Specify which code is used for SYCL and which is used for CUDA, as shown below: Have a single source file that can be compiled with a CUDA compiler for NVIDIA In the first approach, for the maintenance of CUDA/SYCL applications weĮncapsulate SYCL and CUDA using C++ abstractions.Similarities and differences between them.ĭepending on how the code has been written, there are three approaches for how to maintain it. In this chapter we show different SYCL and CUDA examples and demonstrate the ![]()
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